Any percent can be above average(as long as its not 100%) if there are exteme outliers. For example the average us income is $60k while the median(the most common) is 30k. Source: i just searched it. But you get it. In this memes case its incorrect because iq is a bell curve.
Statisticians and smarter people, please correct me if I am wrong since my only experience is one statistics class in college, but this could be true if you have a lot of extreme outliers on the lower end than the upper end.
Averages are just that - an average. If you have 1000 people and 750 of them have IQs below 60 and the rest have “normal” IQs, then your average will skew to the lower IQs. I would wager median and mode would be better for this kind of stuff.
But if 50% of people are above the average, can that truly be an average?
Only if the average is exactly equal to the median.
No, but if you compliment the dumb ones they will work harder for the same amount. Making average common makes business easier.
Any percent can be above average(as long as its not 100%) if there are exteme outliers. For example the average us income is $60k while the median(the most common) is 30k. Source: i just searched it. But you get it. In this memes case its incorrect because iq is a bell curve.
Median isn’t most common, that would be mode. Median is the “middle” value i.e. the value that half of the population are above and half are below.
Statisticians and smarter people, please correct me if I am wrong since my only experience is one statistics class in college, but this could be true if you have a lot of extreme outliers on the lower end than the upper end.
Averages are just that - an average. If you have 1000 people and 750 of them have IQs below 60 and the rest have “normal” IQs, then your average will skew to the lower IQs. I would wager median and mode would be better for this kind of stuff.
Median is a form of average.