A double can represent numbers up to ± 1.79769313486231570x10^308, or roughly 18 with 307 zeroes behind it. You can’t fit that into a long, or even 128 bits. Even though rounding huge doubles is pointless, since only the first dozen digits or so are saved, using any kind of Integer would lead to inconsistencies, and thus potentially bugs.
Makes sense, cause double can represent way bigger numbers than integers.
Also, double can and does in fact represent integers exactly.
Only to 2^54. The amount of integers representable by a long is more. But it can and does represent every int value correctly
*long long, if we’re gonna be taking about C types. A long is commonly limited to 32 bits.
C is irrelevant because this post is about Java and in Java long is 64 bits.
you should never be using these types in c anyway,
(u?)int(8/16/32/64)_tare way more sanedeleted by creator
doubles can hold numbers way larger than even 64-bit ints
A double can represent numbers up to ± 1.79769313486231570x10^308, or roughly 18 with 307 zeroes behind it. You can’t fit that into a long, or even 128 bits. Even though rounding huge doubles is pointless, since only the first dozen digits or so are saved, using any kind of Integer would lead to inconsistencies, and thus potentially bugs.